4(t)=-4.9(t)^2+442.225

Solution for 4(t)=-4.9(t)^2+442.225 equation:

4(t)=-4.9(t)^2+442.225

We move all terms to the left:

4(t)-(-4.9(t)^2+442.225)=0

determiningTheFunctionDomain
-(-4.9t^2+442.225)+4t=0

We get rid of parentheses

4.9t^2+4t-442.225=0

a = 4.9; b = 4; c = -442.225;
Δ = b2-4ac
Δ = 42-4·4.9·(-442.225)
Δ = 8683.61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{8683.61}}{2*4.9}=\frac{-4-\sqrt{8683.61}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{8683.61}}{2*4.9}=\frac{-4+\sqrt{8683.61}}{9.8}
$